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CrazyFroger
@CrazyFroger
August 2021
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log x^2+2x-15 (0.5) ≥ log x^2+2x-15 (x-2)
ПОМОГИТЕ
x^2+2x-15 - основание
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vladkondratev20
Log (x^2+2x-15) 0,5 (> или =) log (x^2+2x-15) (x-2);
0,5 (> или =) (x-2);
-x (> или =) -2-0,5;
-x (> или =) -2,5; :(-1);
х (< или =) 2,5;
Ответ: х (< или =) 2,5.
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Answers & Comments
0,5 (> или =) (x-2);
-x (> или =) -2-0,5;
-x (> или =) -2,5; :(-1);
х (< или =) 2,5;
Ответ: х (< или =) 2,5.