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galinkakondratovich
@galinkakondratovich
October 2021
1
13
Report
log2(4^x-5*2^x+8)>2
необходимо решить неравенство
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kristinchik69
Ответ:
Объяснение:
log2(4^x-5*2^x+8)>2
㏒₂(4ˣ-5*2ˣ+8)
>2, х прегадлежит R
4ˣ-5*2ˣ+8
>
2²
(2²)ˣ-5*2ˣ+8
>4
t²-5t+8
>4
t принадлежит [-∞,1]∪[4,+∞]
2ˣ принадлежит [-∞,1]∪[4,+∞]
2ˣ>4 2ˣ<1
х пренадлежит [-∞,0]∪[2,+∞]
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Answers & Comments
Ответ:
Объяснение:
log2(4^x-5*2^x+8)>2