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holsey
@holsey
July 2022
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Log2(x^2+7x) =3
Помогите, пожалуйста. Очень надо.
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dmitrija7531
Решение:
log2(x^2+7x) =3
log2x^2+7log2x-3=0
x1=-7log2+√49log2^2+12log2/2log2
x2=-7log2-√49log2^2+12log2/2log2
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Answers & Comments
log2(x^2+7x) =3
log2x^2+7log2x-3=0
x1=-7log2+√49log2^2+12log2/2log2
x2=-7log2-√49log2^2+12log2/2log2