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PolinaSyt
@PolinaSyt
March 2022
2
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log3 (13-4^x)>2
логарифмические неравенство, срочно.
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ShirokovP
Verified answer
Log3 (13 - 4^x) > log3 (9)
ОДЗ
4^x < 13
x < log4 (13) ≈ 1,85
13 - 4^x > 9
- 4^x > - 4
4^x < 4
x < 1
+ ОДЗ
x < 1
x < log4 (13) ≈ 1,85
Ответ
x < 1
4 votes
Thanks 7
sangers1959
Verified answer
Log₃(13-4ˣ)>2 ОДЗ: 13-4ˣ>0 4ˣ<13 x<log₄13≈1,85
log₃(13-4ˣ)>log₃9
13-4ˣ>9
4ˣ<4¹
x<1.
1 votes
Thanks 2
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Answers & Comments
Verified answer
Log3 (13 - 4^x) > log3 (9)ОДЗ
4^x < 13
x < log4 (13) ≈ 1,85
13 - 4^x > 9
- 4^x > - 4
4^x < 4
x < 1
+ ОДЗ
x < 1
x < log4 (13) ≈ 1,85
Ответ
x < 1
Verified answer
Log₃(13-4ˣ)>2 ОДЗ: 13-4ˣ>0 4ˣ<13 x<log₄13≈1,85log₃(13-4ˣ)>log₃9
13-4ˣ>9
4ˣ<4¹
x<1.