log2 x- log4 9 + 1/log3 2 + 2 =6 Пожалуйста! !!!!!!!. Created by sonya99051. algebra-ru

log3 2 + 2 =6 Пожалуйста! !!!!!!!...

July 2022 2 3 Report

log2 x- log4 9 + 1/log3 2 + 2 =6
Пожалуйста! !!!!!!!

shakha2017

Verified answer

Формулы :
loga b -loga c=loga b/c
loga b+loga c=loga b*c
1/logb a=loga b
loga^n (b^n) =loga b
Решение :
log2 x-log2 3 +log2 3 +2=6
log2 ((x/3)*3)=6-2
log2 x =4
x=16

3 votes Thanks 2

qmxz 6=log2 642=log2 4log2 x- log2 3 +log2 3 +log2 4= log2 64log2 x*4 =log2 64x*4=64x=64/4=16

1 votes Thanks 1

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