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atorindenis2011
@atorindenis2011
November 2021
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log3 (2x+3)>log3 (x-1)
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Verified answer
Log3 (2x+3)>log3 (x-1)
ОДЗ
x-1>0 x>1
2x+3>0 x>-3/2
x
∈(1 +∞)
снимаем логарифмы, не меняя знака (основание больше 1)
2х+3 > x-1
x>-4
пересекаем ОДЗ
ответ x∈(1 +∞)
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Answers & Comments
Verified answer
Log3 (2x+3)>log3 (x-1)ОДЗ
x-1>0 x>1
2x+3>0 x>-3/2
x∈(1 +∞)
снимаем логарифмы, не меняя знака (основание больше 1)
2х+3 > x-1
x>-4
пересекаем ОДЗ
ответ x∈(1 +∞)