Помогите: Log27 8/ Log3 4. Created by cet1999. matematika-ru

Log3 4...

cet1999 @cet1999

August 2022 1 5 Report

Помогите: Log27 8/ Log3 4

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$\frac{Log_{27}8}{Log_34}= \frac{Log_{3^3}8}{Log_34}= \frac{1}{3}* \frac{Log_38}{Log_34} = \frac{1}{3}*Log_48= \frac{1}{3}Log_{2^2}8= \frac{1}{3}* \frac{1}{2}*Log_28=$

$= \frac{1}{3}* \frac{1}{2}*Log_22^3= \frac{3}{6}= \frac{1}{2}=0.5$

3 votes Thanks 1

oganesbagoyan Loq_3³ 2³ / Loq_3 2² = Loq_3 2 / 2Loq_3 2 =0,5. * * *Loq_a^k M^k =Loq_a M ; Loq_a M^k = kLoq_a M . * * *

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