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Hulk29
@Hulk29
August 2022
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log₀,₂₅32
log⁷√₃3
18·3log₃⁴
log₀,₂₅9·log₉⁴
(7log₇²) в степени log₂⁷
(5log₂⁷) в степени log₅²
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pomoshnik09
1)=log1/4 (2^5)=5*log(2^-2)числа 2=5*-1/2 log2 2=-5/2=-2.5 после логар пишу основание
2)=18*3*2log3 2=108log3 2
3)=log(2^-2) 3²*log(3²) 2²= -1/2*2log2 3*1/2*2*log3 2=1-*1=-1 (форм loga b*logb a=1)
4.5 не знаю
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Answers & Comments
2)=18*3*2log3 2=108log3 2
3)=log(2^-2) 3²*log(3²) 2²= -1/2*2log2 3*1/2*2*log3 2=1-*1=-1 (форм loga b*logb a=1)
4.5 не знаю