Log_4〖(7〗 x+8)=3 Lg(5x-9)=lg(3x+1)
log_7〖(x^2-4x-7)〗=log_7〖(5-3x)〗
Lg(x+2)+lg(x-3)=lg(2x-1)
3〖log〗_27^2 x+5 log_27x-2=0
log_7〖(x^2-4x-7)〗=log_7〖(5-3x)〗
Lg(x+2)+lg(x-3)=lg(2x-1)
3〖log〗_27^2 x+5 log_27x-2=0
More Questions From This User See All