July 2022 1 11 Report
log4(x^2+x)=log 4(x^2+9)
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wangross
wangrosswangross
log_4(x^2+x)=log_4(x^2+9)
ОДЗ:
\left \{ {{x^2+x\ \textgreater \ 0} \atop {x^2+9\ \textgreater \ 0}} \right. ~~~ \left \{ {{x(x+1)\ \textgreater \ 0} \atop {x^2+9\ \textgreater \ 0}} \right. ~~~x\in(-\infty;-1) \text{ U }(0;+\infty)

Решение:
log_4(x^2+x)=log_4(x^2+9) \\ x^2+x=x^2+9 \\ x=9

Ответ: 9
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