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roshko2002
@roshko2002
July 2022
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Логарифм(2х-5) по основанию 2 =-1
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rubilovalex
2x-5>0, 2x>5, x>2,5. Log2 (2x-5)=Log2 1/2; 2x-5=1/2; 2x=5 1/2; x= 5 1/2:2=11/4= 2,75. Ответ: x=2,75.
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