Verified answer

4^(1/2log(4) 49 - log(2) 5)

log(a^k) b^n = n/k log (a) b

log a/b = log a - log b

a^log(a) b = b

1/2 log(4) 49 - log(2) 5 = log(2) 49 - log(2) 5 = log(2) 49/5

4^log(2) 49/5 = (2^2)^log(2) 49/5 = 2^log(2) (49/5)^2 = (49/5)^2