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ainow99
@ainow99
September 2021
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логарифмического неравенстваlg(x+2)>lg4
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ShirokovP
Verified answer
ОДЗ
x ∈ ( - 2; + ∞)
lg(x + 2) > lg4
x + 2 > 4
x > 2
+ ОДЗ
x ∈ ( 2; + ∞)
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Answers & Comments
Verified answer
ОДЗx ∈ ( - 2; + ∞)
lg(x + 2) > lg4
x + 2 > 4
x > 2
+ ОДЗ
x ∈ ( 2; + ∞)