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jsnshaiajjajwjw
@jsnshaiajjajwjw
May 2022
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ЛОГАРИМЫ
ДАМ 39 баллов
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sedinalana
1
(1-3x)/(x+1)>0
x=1/3 x=-1
_ + _
------(-1)-------------(1/3)-------------
x∈(-1;1/3)
Ответ б
2
y`=(2x-6)/(x²-6x+11)ln4
2x-6=0
2x=6
x=3
y(3)=log(4)(9-18+11)=log(4)2=0,5
Ответ г
3
3-2x>0⇒x<1,5
log(7)(3-2x)=log(3)(∛64*3/4)
log(7)(3-2x)=log(3)3
log(7)(3-2x)=1
3-2x=7
2x=3-7
2x=-4
x=-2
Ответ а
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Answers & Comments
(1-3x)/(x+1)>0
x=1/3 x=-1
_ + _
------(-1)-------------(1/3)-------------
x∈(-1;1/3)
Ответ б
2
y`=(2x-6)/(x²-6x+11)ln4
2x-6=0
2x=6
x=3
y(3)=log(4)(9-18+11)=log(4)2=0,5
Ответ г
3
3-2x>0⇒x<1,5
log(7)(3-2x)=log(3)(∛64*3/4)
log(7)(3-2x)=log(3)3
log(7)(3-2x)=1
3-2x=7
2x=3-7
2x=-4
x=-2
Ответ а