log(основание: x^2-2x+1)(3-x) <= 1
log(осн x^2-2x+1)<=1
x^2-2x+1<=3-x
x^2-x-2<=0
x1+x2=1 2-1=1
x1*x2=-2 2*(-1)=-2
ОДЗ: x^2-2x+1>0
x>1
Ответ: 2
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Answers & Comments
log(осн x^2-2x+1)<=1
x^2-2x+1<=3-x
x^2-x-2<=0
x1+x2=1 2-1=1
x1*x2=-2 2*(-1)=-2
ОДЗ: x^2-2x+1>0
x>1
Ответ: 2