люди плиз помогите алгебра №201-203пж желательно подробно. Created by помогитеD1fhgg. algebra-ru

Известная формула:То есть значения "х" располагаются левее (-а) и правее (а) .Вместо "х" может быть записано любое выражение, а вместо "а" - любое число. В формуле надо только заменить "х" и "а" на те выражения или числа, которые заданы в условии."х" принимает значения из промежутка между (-а) и (а) . огромное спасибо) Новые вопросы в Алгебра ДАЮ 40 БАЛЛОВ. ПОМОГИТЕ РЕШИТЬ ПОЖАЛУЙСТА!! Является ли группой данное множество М относительно операции умножения. упростите вырожение (3√5+√125)√5 Помогите мне с 5 заданием пожалуйста. Очень срочно Буду благодарна Шесть игроков волейбольной команды выбирают себе двузначные номера на футболки. Номера, в свою очередь, составляются из цифр 2, 4, 6, 8 при условии, ч … то цифры в номере различны. Сколькими способами можно осуществить присвоение номеров игрокам команды? Для последнего задания подсказка: работает правило произведения 1. Выбор номера: … способов 2. Выбор игроков: … способов 3. (1)×(2) На карте изображен рисунок 14 см и масштабом 1:500.000. Найти длину рисунка, если масштаб равен 1:750.000 Алиса решила, что вместе с другом сначала полетит в Италию. Она так давно хотела увидеть Колизей. Но вот незадача: она забыла, во сколько взлетает её … самолёт. Чтобы узнать, через сколько он вылетает, нужно решить пример. Столяр вырезал полку для шкафа в виде пятиугольника, в основе — квадрат 350 × 350 мм, от которого отрезан один угол (см. рисунок) так, что длина скош … енной кромки равна 210 мм. Теперь столяру нужно вырезать похожую полку, у которой три кромки выдаются на 30 мм по сравнению с первой полкой. Какова будет длина скошенной кромки у второй полки? Считайте tg 22, 5° ≈ 0, 4142. Результат округлите до целого числа миллиметров. Запишите решение и ответ. 15/а сколько будет ? Найдите значение выражения 15 (ab^2)^3/a^4 b^6при a = 3 и b = 4,22. ПРОШУ! ПОМОГИТЕ Все балы Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . 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(1)\u00d7(2)"},{"id":48647341,"content":"\u041d\u0430 \u043a\u0430\u0440\u0442\u0435 \u0438\u0437\u043e\u0431\u0440\u0430\u0436\u0435\u043d \u0440\u0438\u0441\u0443\u043d\u043e\u043a 14 \u0441\u043c \u0438 \u043c\u0430\u0441\u0448\u0442\u0430\u0431\u043e\u043c 1:500.000. \u041d\u0430\u0439\u0442\u0438 \u0434\u043b\u0438\u043d\u0443 \u0440\u0438\u0441\u0443\u043d\u043a\u0430, \u0435\u0441\u043b\u0438 \u043c\u0430\u0441\u0448\u0442\u0430\u0431 \u0440\u0430\u0432\u0435\u043d 1:750.000"},{"id":48647230,"content":"\u0410\u043b\u0438\u0441\u0430 \u0440\u0435\u0448\u0438\u043b\u0430, \u0447\u0442\u043e \u0432\u043c\u0435\u0441\u0442\u0435 \u0441 \u0434\u0440\u0443\u0433\u043e\u043c \u0441\u043d\u0430\u0447\u0430\u043b\u0430 \u043f\u043e\u043b\u0435\u0442\u0438\u0442 \u0432 \u0418\u0442\u0430\u043b\u0438\u044e. \u041e\u043d\u0430 \u0442\u0430\u043a \u0434\u0430\u0432\u043d\u043e \u0445\u043e\u0442\u0435\u043b\u0430 \u0443\u0432\u0438\u0434\u0435\u0442\u044c \u041a\u043e\u043b\u0438\u0437\u0435\u0439. \u041d\u043e \u0432\u043e\u0442 \u043d\u0435\u0437\u0430\u0434\u0430\u0447\u0430: \u043e\u043d\u0430 \u0437\u0430\u0431\u044b\u043b\u0430, \u0432\u043e \u0441\u043a\u043e\u043b\u044c\u043a\u043e \u0432\u0437\u043b\u0435\u0442\u0430\u0435\u0442 \u0435\u0451 \u0441\u0430\u043c\u043e\u043b\u0451\u0442. \u0427\u0442\u043e\u0431\u044b \u0443\u0437\u043d\u0430\u0442\u044c, \u0447\u0435\u0440\u0435\u0437 \u0441\u043a\u043e\u043b\u044c\u043a\u043e \u043e\u043d \u0432\u044b\u043b\u0435\u0442\u0430\u0435\u0442, \u043d\u0443\u0436\u043d\u043e \u0440\u0435\u0448\u0438\u0442\u044c \u043f\u0440\u0438\u043c\u0435\u0440.\u200b"},{"id":48647163,"content":"\n\u0421\u0442\u043e\u043b\u044f\u0440 \u0432\u044b\u0440\u0435\u0437\u0430\u043b \u043f\u043e\u043b\u043a\u0443 \u0434\u043b\u044f \u0448\u043a\u0430\u0444\u0430 \u0432 \u0432\u0438\u0434\u0435 \u043f\u044f\u0442\u0438\u0443\u0433\u043e\u043b\u044c\u043d\u0438\u043a\u0430, \u0432 \u043e\u0441\u043d\u043e\u0432\u0435 \u2014 \u043a\u0432\u0430\u0434\u0440\u0430\u0442 350 \u00d7 350 \u043c\u043c, \u043e\u0442 \u043a\u043e\u0442\u043e\u0440\u043e\u0433\u043e\n\u043e\u0442\u0440\u0435\u0437\u0430\u043d \u043e\u0434\u0438\u043d \u0443\u0433\u043e\u043b (\u0441\u043c. \u0440\u0438\u0441\u0443\u043d\u043e\u043a) \u0442\u0430\u043a, \u0447\u0442\u043e \u0434\u043b\u0438\u043d\u0430 \u0441\u043a\u043e\u0448\u0435\u043d\u043d\u043e\u0439 \u043a\u0440\u043e\u043c\u043a\u0438 \u0440\u0430\u0432\u043d\u0430 210 \u043c\u043c. \u0422\u0435\u043f\u0435\u0440\u044c \u0441\u0442\u043e\u043b\u044f\u0440\u0443 \u043d\u0443\u0436\u043d\u043e \u0432\u044b\u0440\u0435\u0437\u0430\u0442\u044c \u043f\u043e\u0445\u043e\u0436\u0443\u044e \u043f\u043e\u043b\u043a\u0443, \u0443 \u043a\u043e\u0442\u043e\u0440\u043e\u0439 \u0442\u0440\u0438 \u043a\u0440\u043e\u043c\u043a\u0438 \u0432\u044b\u0434\u0430\u044e\u0442\u0441\u044f \u043d\u0430 30 \u043c\u043c \u043f\u043e \u0441\u0440\u0430\u0432\u043d\u0435\u043d\u0438\u044e \u0441 \u043f\u0435\u0440\u0432\u043e\u0439 \u043f\u043e\u043b\u043a\u043e\u0439. \u041a\u0430\u043a\u043e\u0432\u0430 \u0431\u0443\u0434\u0435\u0442 \u0434\u043b\u0438\u043d\u0430 \u0441\u043a\u043e\u0448\u0435\u043d\u043d\u043e\u0439 \u043a\u0440\u043e\u043c\u043a\u0438 \u0443 \u0432\u0442\u043e\u0440\u043e\u0439 \u043f\u043e\u043b\u043a\u0438? \u0421\u0447\u0438\u0442\u0430\u0439\u0442\u0435\ntg 22, 5\u00b0 \u2248 0, 4142. \u0420\u0435\u0437\u0443\u043b\u044c\u0442\u0430\u0442 \u043e\u043a\u0440\u0443\u0433\u043b\u0438\u0442\u0435 \u0434\u043e \u0446\u0435\u043b\u043e\u0433\u043e \u0447\u0438\u0441\u043b\u0430 \u043c\u0438\u043b\u043b\u0438\u043c\u0435\u0442\u0440\u043e\u0432.\n\u0417\u0430\u043f\u0438\u0448\u0438\u0442\u0435 \u0440\u0435\u0448\u0435\u043d\u0438\u0435 \u0438 \u043e\u0442\u0432\u0435\u0442."},{"id":48646875,"content":"15\/\u0430 \u0441\u043a\u043e\u043b\u044c\u043a\u043e \u0431\u0443\u0434\u0435\u0442 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люди плиз помогите алгебра №201-203пж желательно подробно...

помогитеD1fhgg @помогитеD1fhgg

March 2022 1 126 Report

люди плиз помогите алгебра №201-203
пж желательно подробно

Answers & Comments

NNNLLL54

Verified answer

Известная формула:

$|x|>a\; \; \Rightarrow \; \; \left [ {{x>a} \atop {x$

То есть значения "х" располагаются левее (-а) и правее (а) .

Вместо "х" может быть записано любое выражение, а вместо "а" - любое число. В формуле надо только заменить "х" и "а" на те выражения или числа, которые заданы в условии.

$201)\; \; \Big |\frac{3x+1}{x-5}\Big |\geq 1\; \; \to \; \; \left [ {{\frac{3x+1}{x-5}\geq 1} \atop {\frac{3x+1}{x-5}\leq -1}} \right. \\\\a)\; \; \frac{3x+1}{x-5}-1\geq 0\; ,\; \; \frac{3x+1-(x-5)}{x-5}\geq 0\; ,\; \; \frac{2x+6}{x-5}\geq 0\; ,\; \; \frac{2(x+3)}{x-5}\geq 0\; ,\\\\+++[-3]---(5)+++\\\\x\in (-\infty ,-3\; ]\cup (5,+\infty )\\\\b)\; \; \frac{3x+1}{x-5}+1\leq 0\; ,\; \; \frac{3x+1+x-5}{x-5} \leq 0\; ,\; \; \frac{4x-4}{x-5}\leq 0\; ,\; \frac{4(x-1)}{x-5}\leq 0\; ,\\\\+++[\; 1\; ]---(5)+++$

$x\in [\; 1,5)\\\\c)\; \; \left [ {{x\in (-\infty ,-3\, ]\cup (5,+\infty )} \atop {x\in [\, 1,5)}} \right. \; \; \Rightarrow \; \; \underline {x\in (-\infty ,-3\, ]\cup [\, 1,5)\cup (5,+\infty )}\\\\\\203)\; \; |3x-2|>2x+1\; \; \Rightarrow \; \; \left \{ {{3x-2>2x+1} \atop {3x-22x+1\; ,\; \; x>3\\\\b)\; \; 3x-2$