TheGorilla Lambda(max) = hc/A(выхода) => A = hc/labmda(max) = (6.6×10^-34 × 3×10^8)/550×10^-9 = 0.036×10^-17 Дж
E(фотонов) = А + Е(кинетическая) = 3,6×10^-19 + 1.8×10^-19 = 5.4×10^-19
E = hc/lambda => lambda = hc/E = 19.8×10^-26/5.4×10^-19 =3.6(6)×10^-7