Home
О нас
Products
Services
Регистрация
Войти
Поиск
19mar2003
@19mar2003
October 2021
1
7
Report
M, N, v, m, V(н.у.): SiO2; PH3 газ; CO2 газ
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
zubareva45
Verified answer
N(SiO₂) = 1моль
M(SiO₂) = 28+32=60г./моль
m(SiO₂) = 60г.
N(SiO₂) = 6·10²³ молекул
V(н.у.)(SiO₂) = m(SiO₂)÷ρ(SiO₂)=60г.÷1.5г./см³=40см³
n(PH₃) =1моль
M(PH₃) = 31+3 =34г./моль
m(PH₃) = 34г
N(PH₃) = 6·10²³ молекул
V(н.у.)(PH₃) = n(PH₃)х Vm = 1мольx 22.4л./моль= 22,4л
n(CO
₂
) = 1моль
M(CO₂) = 12+32 = 44г./моль
m(CO₂) = 44г.
N(CO₂) =
6·10²³ молекул
V(н.у.)(CO₂) =n(CO₂)х Vm = 1мольх22,4л./моль=22,4л.
2 votes
Thanks 1
×
Report "M, N, v, m, V(н.у.): SiO2; PH3 газ; CO2 газ..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
N(SiO₂) = 1мольM(SiO₂) = 28+32=60г./моль
m(SiO₂) = 60г.
N(SiO₂) = 6·10²³ молекул
V(н.у.)(SiO₂) = m(SiO₂)÷ρ(SiO₂)=60г.÷1.5г./см³=40см³
n(PH₃) =1моль
M(PH₃) = 31+3 =34г./моль
m(PH₃) = 34г
N(PH₃) = 6·10²³ молекул
V(н.у.)(PH₃) = n(PH₃)х Vm = 1мольx 22.4л./моль= 22,4л
n(CO₂) = 1моль
M(CO₂) = 12+32 = 44г./моль
m(CO₂) = 44г.
N(CO₂) = 6·10²³ молекул
V(н.у.)(CO₂) =n(CO₂)х Vm = 1мольх22,4л./моль=22,4л.