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19mar2003
@19mar2003
October 2021
1
8
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M, N, v, m, V(н.у.): SiO2; PH3 газ; CO2 газ
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zubareva45
Verified answer
N(SiO₂) = 1моль
M(SiO₂) = 28+32=60г./моль
m(SiO₂) = 60г.
N(SiO₂) = 6·10²³ молекул
V(н.у.)(SiO₂) = m(SiO₂)÷ρ(SiO₂)=60г.÷1.5г./см³=40см³
n(PH₃) =1моль
M(PH₃) = 31+3 =34г./моль
m(PH₃) = 34г
N(PH₃) = 6·10²³ молекул
V(н.у.)(PH₃) = n(PH₃)х Vm = 1мольx 22.4л./моль= 22,4л
n(CO
₂
) = 1моль
M(CO₂) = 12+32 = 44г./моль
m(CO₂) = 44г.
N(CO₂) =
6·10²³ молекул
V(н.у.)(CO₂) =n(CO₂)х Vm = 1мольх22,4л./моль=22,4л.
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Answers & Comments
Verified answer
N(SiO₂) = 1мольM(SiO₂) = 28+32=60г./моль
m(SiO₂) = 60г.
N(SiO₂) = 6·10²³ молекул
V(н.у.)(SiO₂) = m(SiO₂)÷ρ(SiO₂)=60г.÷1.5г./см³=40см³
n(PH₃) =1моль
M(PH₃) = 31+3 =34г./моль
m(PH₃) = 34г
N(PH₃) = 6·10²³ молекул
V(н.у.)(PH₃) = n(PH₃)х Vm = 1мольx 22.4л./моль= 22,4л
n(CO₂) = 1моль
M(CO₂) = 12+32 = 44г./моль
m(CO₂) = 44г.
N(CO₂) = 6·10²³ молекул
V(н.у.)(CO₂) =n(CO₂)х Vm = 1мольх22,4л./моль=22,4л.