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Angello4ek
@Angello4ek
July 2022
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Определить силу тяжести 7,8,9,15,20 литров молока, если плотность молока 930 кг/м³
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fatt52
Verified answer
Дано
V1=0.007 м³
V2=0.008 м³
V3=0.009 м³
V4=0.015 м³
V5=0.02 м³
ρ=930 кг/м³
g=10 Н/кг
===
F1=?---F5=?
================
F=m*g
m=ρ*V
F1=ρ*V1*g=930*0.007*10=65.1 H
F2=ρ*V2*g=930*0.008*10=74.4 H
F3=ρ*V3*g=930*0.009*10=83.7 H
F4=ρ*V4*g=930*0.015*10=139.5 H
F5=ρ*V5*g=930*0.02*10=186 H
======================================
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Angello4ek
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Answers & Comments
Verified answer
ДаноV1=0.007 м³
V2=0.008 м³
V3=0.009 м³
V4=0.015 м³
V5=0.02 м³
ρ=930 кг/м³
g=10 Н/кг
===
F1=?---F5=?
================
F=m*g
m=ρ*V
F1=ρ*V1*g=930*0.007*10=65.1 H
F2=ρ*V2*g=930*0.008*10=74.4 H
F3=ρ*V3*g=930*0.009*10=83.7 H
F4=ρ*V4*g=930*0.015*10=139.5 H
F5=ρ*V5*g=930*0.02*10=186 H
======================================