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nastya153592
@nastya153592
August 2022
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под действием какой силы пружина имеющая жесткость 4000 н/м сжимается на 0,01 м?
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Математика666
F = k*x
F=4000*0,01
40 Н
8 votes
Thanks 17
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Answers & Comments
F = k*x
F=4000*0,01
40 Н