Ответ:
[tex]V_{p} =[/tex] 32 м³
Объяснение:
Дано:
[tex]m_{1} =[/tex] 1400 кг
[tex]V =[/tex] 34 м³
[tex]\rho_{v} =[/tex] 1000 кг/м³
[tex]\rho_{l} =[/tex] 900 кг/м³
Найти:
[tex]V_{p} \ - \ ?[/tex]
----------------------------
Решение:
[tex]F_{A} = \rho_{v}gV_{p}[/tex]
[tex]\rho = \dfrac{m}{V} \Longrightarrow m = \rho V[/tex]
[tex]\boxed{m_{l} = \rho_{l} V}[/tex]
[tex]F_{T} = mg = (m_{l} + m_{1})g = (\rho_{l} V}+m_{1})g[/tex]
[tex]\overrightarrow{F_{A}} + \overrightarrow{F_{T}} = m\vec{a}; (a = 0)[/tex] - по второму закону Ньютона
[tex]\overrightarrow{F_{A}} + \overrightarrow{F_{T}} = 0[/tex]
[tex]OY: -F_{A} + F_{T} = 0[/tex]
[tex]F_{T} = F_{A}[/tex]
[tex](\rho_{l} V+m_{1})g = \rho_{v}gV_{p} \Longrightarrow V_{p} = \dfrac{(\rho_{l} V+m_{1})g}{\rho_{v}g} = \dfrac{\rho_{l} V+m_{1}}{\rho_{v}}[/tex]
[tex]\boxed{V_{p} = \dfrac{\rho_{l} V+m_{1}}{\rho_{v}} }[/tex]
[tex]V_{p} =[/tex] (900 кг/м³ * 34 м³ + 1400 кг) / (1000 кг/м³) = 32 м³
Ответ: [tex]V_{p} =[/tex] 32 м³.
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Verified answer
Ответ:
[tex]V_{p} =[/tex] 32 м³
Объяснение:
Дано:
[tex]m_{1} =[/tex] 1400 кг
[tex]V =[/tex] 34 м³
[tex]\rho_{v} =[/tex] 1000 кг/м³
[tex]\rho_{l} =[/tex] 900 кг/м³
Найти:
[tex]V_{p} \ - \ ?[/tex]
----------------------------
Решение:
[tex]F_{A} = \rho_{v}gV_{p}[/tex]
[tex]\rho = \dfrac{m}{V} \Longrightarrow m = \rho V[/tex]
[tex]\boxed{m_{l} = \rho_{l} V}[/tex]
[tex]F_{T} = mg = (m_{l} + m_{1})g = (\rho_{l} V}+m_{1})g[/tex]
[tex]\overrightarrow{F_{A}} + \overrightarrow{F_{T}} = m\vec{a}; (a = 0)[/tex] - по второму закону Ньютона
[tex]\overrightarrow{F_{A}} + \overrightarrow{F_{T}} = 0[/tex]
[tex]OY: -F_{A} + F_{T} = 0[/tex]
[tex]F_{T} = F_{A}[/tex]
[tex](\rho_{l} V+m_{1})g = \rho_{v}gV_{p} \Longrightarrow V_{p} = \dfrac{(\rho_{l} V+m_{1})g}{\rho_{v}g} = \dfrac{\rho_{l} V+m_{1}}{\rho_{v}}[/tex]
[tex]\boxed{V_{p} = \dfrac{\rho_{l} V+m_{1}}{\rho_{v}} }[/tex]
[tex]V_{p} =[/tex] (900 кг/м³ * 34 м³ + 1400 кг) / (1000 кг/м³) = 32 м³
Ответ: [tex]V_{p} =[/tex] 32 м³.