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Vadsport1
@Vadsport1
July 2022
1
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Срочно мне.
Рыба горбуша находится на глубине 600м и имеет площадь поверхности 750см^2. С какой силой она сдавливается водой? Р=1030кг/м^3.
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UmbertoVargas
Verified answer
P = F / S => F = P S = pgh S
F = 10^(4)*6*10^(2) * 75*10^(-3) = 450 кН
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Answers & Comments
Verified answer
P = F / S => F = P S = pgh SF = 10^(4)*6*10^(2) * 75*10^(-3) = 450 кН