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varyaprokofeva
@varyaprokofeva
November 2021
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СРОЧНО!!
Чему равно ускорение,сообщаемое электрону в электрическом поле напряжённостью 2,7 кВ/м?
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aleksobuhov350
Verified answer
F=qE; F=ma; ma=qE; a=qE/m; a=(1.6*10^-19*2700)/9.1*10^-31≈4.7*10^14 м/с^2
Ответ: a=4.7*10^14 м/с^2
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Answers & Comments
Verified answer
F=qE; F=ma; ma=qE; a=qE/m; a=(1.6*10^-19*2700)/9.1*10^-31≈4.7*10^14 м/с^2Ответ: a=4.7*10^14 м/с^2