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Goraci
@Goraci
June 2022
1
10
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На сколько уменьшится длина пружины, если ее сжать силой 20 Н? Жесткость пружины равна 400 Н/м .
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AnnaTakaho
F=kx
x=F/k=20/400=0,05 м
или
5см
2 votes
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x=F/k=20/400=0,05 м
или
5см