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Mg + 2HCl = MgCl2 + H2
m(HCl) = 73 г
n(HCl) = m/M = 73/36.5 = 2 моль
n(HCl) = nH2 = 2 моль
V(H2) = Vm × n = 22.4 × 4 = 44.8 л
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Answers & Comments
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Mg + 2HCl = MgCl2 + H2
m(HCl) = 73 г
n(HCl) = m/M = 73/36.5 = 2 моль
n(HCl) = nH2 = 2 моль
V(H2) = Vm × n = 22.4 × 4 = 44.8 л
пхпх сорямба