Ответ:

дано

VCxHy = 1 L

m(CxHy) = 3.84 g

W(C) = 83.72 % = 0.8372

----------------

CxHy - ?

M(CxHy) = Vm * m(CxHy) / V(CxHy) = 22.4*3.84 / 1 = 86 g/mol

W(H) = 100% - W(C) = 100 - 83.72% = 16.26% = 0.1626

CxHy / 86 = 0.8372 / 12 : 0.1626/1 =  6 : 14

C6H14

M(C6H14) = 12*7+1*14 = 86 g/mol

ответ ГЕКСАН

Объяснение: