СхН2хBr2
M(Br2)=160
w(Br2)=79,21%
w(C[Hy)=100-79,21=20,79
M(CxHy)=160*20,79/79,21=42
12x+2x=42
14x=42
x=42/14=3
n(C)=3
N(H)=2*3=6
C3H6Br2
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
СхН2хBr2
M(Br2)=160
w(Br2)=79,21%
w(C[Hy)=100-79,21=20,79
M(CxHy)=160*20,79/79,21=42
12x+2x=42
14x=42
x=42/14=3
n(C)=3
N(H)=2*3=6
C3H6Br2