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Anastasia3103777
@Anastasia3103777
August 2021
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Масова частка сполуки H2SO3; Fe2(SO4)3
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krioira
Mr(
H2SO3)=2*1+32+3*16=82
W(H)=2/82=0.02=2%
W(S)=32/82=0.39=39%
W(O)=48/82=0.59=59%
Mr(
Fe2(SO4)3)=2*56+3*32+12*16=400
W(Fe)=112/400=0.28=28%
W(S)=96/400=0.24=24%
W(O)=192/400=0.48=48%
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Answers & Comments
W(H)=2/82=0.02=2%
W(S)=32/82=0.39=39%
W(O)=48/82=0.59=59%
Mr(Fe2(SO4)3)=2*56+3*32+12*16=400
W(Fe)=112/400=0.28=28%
W(S)=96/400=0.24=24%
W(O)=192/400=0.48=48%