Mr(C₆H₁₂O₆) ≈ 180
Ar(C) ≈ 12
ω(C) = (n * Ar(C)) / Mr(C₆H₁₂O₆) = (6 * 12) / 180 = 0,4 = 40%
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Mr(C₆H₁₂O₆) ≈ 180
Ar(C) ≈ 12
ω(C) = (n * Ar(C)) / Mr(C₆H₁₂O₆) = (6 * 12) / 180 = 0,4 = 40%