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masha01012000
@masha01012000
July 2022
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Масса 33,6л паров бензола равна:
А. 39 г
Б. 78 г
В. 107 г
Г. 156 г
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yula03
Сперва найдем n=v\vm=33,6л/22,4л\моль=1.5 моль
M(C6H6)=12*6+6=78
m=M*n=1.5*78=117г
Ответ:117г
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Answers & Comments
M(C6H6)=12*6+6=78
m=M*n=1.5*78=117г
Ответ:117г