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vadik92001
@vadik92001
July 2022
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Масса натрия которая потребуется для получения 33,6 л водорода при взаимодействии натрия с водой
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Masnavichemist
M. 33.6
2na + 2h2o= 2naoh+ h2
46. 22.4
m=46*33.6/22.4=69
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Answers & Comments
2na + 2h2o= 2naoh+ h2
46. 22.4
m=46*33.6/22.4=69