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DashaLdf
@DashaLdf
September 2021
1
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массовая доля химического элемента водорода в молекуле метанола составляет СН4О
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IrVB
W% = Ar*n*100%/Mr
Mr(CH4O) = 32
Ar(H) = 1
W(H)% = 1*4*100/32=
12,5%
2 votes
Thanks 2
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Answers & Comments
Mr(CH4O) = 32
Ar(H) = 1
W(H)% = 1*4*100/32=12,5%