Mr (CaCl₂) = Ar (Ca) + Ar (Cl) × 2 = 40 + 35.5 × 2 = 111
ω (Ca) = N × Ar (Ca) × 100% / Mr (CaCl2) = 1 × 40 × 100% ÷ 111 = 36.04%
ω (Cl) = 100% - 36.04% = 63.96%
Ответ. 4
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Mr (CaCl₂) = Ar (Ca) + Ar (Cl) × 2 = 40 + 35.5 × 2 = 111
ω (Ca) = N × Ar (Ca) × 100% / Mr (CaCl2) = 1 × 40 × 100% ÷ 111 = 36.04%
ω (Cl) = 100% - 36.04% = 63.96%
Ответ. 4