MgSO4*xH2O
ω (H2O)=51.2% -> 0.512
n(H2O) - ?
M(Mg)=24/г/моль
M(MgSO4*xH2O)=24+32+(16*4)+18х
M(MgSO4*xH2O)=120+18х
Берем 1 моль в-ва:
0,512/1 = 25/120+18х
120+18х=25/0,512
18х=46-120
18х=74
Х=74/18
Х=4
MgSO4*4H2O
тетрагидрат MgSO4
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MgSO4*xH2O
ω (H2O)=51.2% -> 0.512
n(H2O) - ?
M(Mg)=24/г/моль
M(MgSO4*xH2O)=24+32+(16*4)+18х
M(MgSO4*xH2O)=120+18х
Берем 1 моль в-ва:
0,512/1 = 25/120+18х
120+18х=25/0,512
18х=46-120
18х=74
Х=74/18
Х=4
MgSO4*4H2O
тетрагидрат MgSO4