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shetininaanna
@shetininaanna
June 2022
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массовая доля сульфата меди 2 в растворе полученном при растворении 50г CuSO4 в 200 гр воды, составляет
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Senpoliya
Verified answer
M(р-ра) = 50 г + 200 г = 250 г
w%(CuSO₄)
= 50 г : 250 г * 100 % =
2 %
1 votes
Thanks 9
Senpoliya
Shetininaanna, спасибо за лучший )
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Answers & Comments
Verified answer
M(р-ра) = 50 г + 200 г = 250 гw%(CuSO₄) = 50 г : 250 г * 100 % = 2 %