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ergfghrth
@ergfghrth
August 2022
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Массовая доля в соединении азота 46.67%, кислорода 53,33%. Установите молекулярную формулу вещества?
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anassstass
Молекулярная формула вещества – NO – оксид азота (II)
M (NO) = 14 + 16 = 30 г/моль
w (N) = 14 / 30 = 46,666 ~ 46,67%
w (O) = 16 / 30 = 53,333 ~ 53,33%
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Answers & Comments
M (NO) = 14 + 16 = 30 г/моль
w (N) = 14 / 30 = 46,666 ~ 46,67%
w (O) = 16 / 30 = 53,333 ~ 53,33%