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0045655433
@0045655433
August 2022
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Метод электронного баланса
1.C+O2=CO
2.2C+O2=2CO2
3.Ca+C=CaC2
4.C+H2O=CO+H2
5.Fe2O3+C=CO+Fe
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mrvladimir2
Verified answer
2C⁰+O₂⁰ = 2C⁺²O⁻²
C⁰ - 2e⁻ = C⁺² | 2 - восстан-ль
O₂⁰ + 4e = 2O⁻² | 1 - оксл-ль
2С⁺²O⁻² + O₂⁰ = 2C⁺⁴O₂⁻²
C⁰-4e⁻ = C⁺⁴ | 1 - восст-ль
O₂⁰+4e⁻ = 2O⁻² |1 - окисдлитель
Ca⁰ + C⁰ = Ca⁺²C₂⁻¹
Ca⁰ - 2e⁻ = Ca⁺² | 1
2C⁰ + 2e⁻ = 2C⁻¹ | 1
C⁰+H₂⁺O = C⁺²O + H₂
C⁰ - 2e⁻ = C⁺² | 1 восст-ль
2H⁺ + 2e⁻ = H₂⁰ | 1 окисл-ль
Fe₂⁺³O₃ + 3C⁺²O = 2Fe⁰ + 3C⁺⁴O2
Fe⁺³ + 3e⁻ = Fe⁰ | 2 окисл-ль
C⁺² - 2e⁻ = C⁺⁴ | 3 восст-ль
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Answers & Comments
Verified answer
2C⁰+O₂⁰ = 2C⁺²O⁻²C⁰ - 2e⁻ = C⁺² | 2 - восстан-ль
O₂⁰ + 4e = 2O⁻² | 1 - оксл-ль
2С⁺²O⁻² + O₂⁰ = 2C⁺⁴O₂⁻²
C⁰-4e⁻ = C⁺⁴ | 1 - восст-ль
O₂⁰+4e⁻ = 2O⁻² |1 - окисдлитель
Ca⁰ + C⁰ = Ca⁺²C₂⁻¹
Ca⁰ - 2e⁻ = Ca⁺² | 1
2C⁰ + 2e⁻ = 2C⁻¹ | 1
C⁰+H₂⁺O = C⁺²O + H₂
C⁰ - 2e⁻ = C⁺² | 1 восст-ль
2H⁺ + 2e⁻ = H₂⁰ | 1 окисл-ль
Fe₂⁺³O₃ + 3C⁺²O = 2Fe⁰ + 3C⁺⁴O2
Fe⁺³ + 3e⁻ = Fe⁰ | 2 окисл-ль
C⁺² - 2e⁻ = C⁺⁴ | 3 восст-ль