July 2021 0 8 Report
Метод подстановки функция 2х-3(2у+1)=15 3(х+1)+3у=2у-2        4у+20=2(3х-4у)-4 16-(5х+2у)=3х-2у       4(х-у)=-2 3х-7у=-2.5-2(х+у)       2(х+у)=8 14-3(х-у)=5у-х 
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