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Anecol25
@Anecol25
August 2022
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Методом подстановки.
x2-3y=1
x-2y=1
Помогите пж
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Darelin
X2-3y=1
x=1+2y
(1+2y)2-3y=1
1+4y+4y2-3y-1=0
4y2+y=0
y(4y+1)=0
y=0 y=-1/4
x=1 x=1/2
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Thanks 0
SatanWolf666
Х^2-3y=1
x=1+2y
(1+2y)^2-3y=1
x=1+2y
1+4y+4y^2-3y=1
x=1+2y
4y^2+y=0
x=1+2y
y(4y+1)=0
x=1+2y
y1=0
4y+1=0
x=1+2y
y1=0
4y=-1
x=1+2y
y1=0
y2= -(1/4)
x1=1+2*0
x2=1+2*(-1/4)
y1=0
y2= -(1/4)
x1=1
x2=1-1/2
y1=0
y2= -(1/4)
x1=1
x2=1/2=0,5
0 votes
Thanks 0
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Answers & Comments
x=1+2y
(1+2y)2-3y=1
1+4y+4y2-3y-1=0
4y2+y=0
y(4y+1)=0
y=0 y=-1/4
x=1 x=1/2
x=1+2y
(1+2y)^2-3y=1
x=1+2y
1+4y+4y^2-3y=1
x=1+2y
4y^2+y=0
x=1+2y
y(4y+1)=0
x=1+2y
y1=0
4y+1=0
x=1+2y
y1=0
4y=-1
x=1+2y
y1=0
y2= -(1/4)
x1=1+2*0
x2=1+2*(-1/4)
y1=0
y2= -(1/4)
x1=1
x2=1-1/2
y1=0
y2= -(1/4)
x1=1
x2=1/2=0,5