m(HNO3)= 12,6г +Cu V(NO2)-?. Created by LeraHate. himiya-ru

m(HNO3)= 12,6г +Cu V(NO2)-?...

July 2022 1 1 Report

m(HNO3)= 12,6г
+Cu
V(NO2)-?

Answers & Comments

Ironchik100 4HNO3 + Cu = Cu(NO3)2 + 2NO2 + 2H2O
n(HNO3) = m/M = 12.6/63 = 0.2 моль
Из уравнения реакции:
n(NO2) = 0.2*2/4 = 0.1 моль
V(NO2) = n*Vm = 0.1*22.4 = 2.24 л

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ukazhite mezhdu kakimi veshestvami proizojdut himicheskie reakcii a med i rastvo

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