дано
V(C2H5OH) = 143.75 mL
p(C2H5OH) = 0.8 g/mL
--------------------------------
m(C2H5Br)-?
C2H5Br+NaOH-->C2H5OH+NaBr
m(C2H5OH) = V(C2H5OH) * p(C2H5OH) = 143.75 * 0.8 = 115 g
M(C2H5OH) = 46 g/mol
n(C2H5OH) = m/M = 115 / 46 = 2.5 mol
n(C2H5Br) = n(C2H5OH) = 2.5 mol
M(C2H5Br)= 109 g/mol
m(C2H5Br) = n*M = 2.5 * 109 = 272.5 g
ответ 272.5 г
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дано
V(C2H5OH) = 143.75 mL
p(C2H5OH) = 0.8 g/mL
--------------------------------
m(C2H5Br)-?
C2H5Br+NaOH-->C2H5OH+NaBr
m(C2H5OH) = V(C2H5OH) * p(C2H5OH) = 143.75 * 0.8 = 115 g
M(C2H5OH) = 46 g/mol
n(C2H5OH) = m/M = 115 / 46 = 2.5 mol
n(C2H5Br) = n(C2H5OH) = 2.5 mol
M(C2H5Br)= 109 g/mol
m(C2H5Br) = n*M = 2.5 * 109 = 272.5 g
ответ 272.5 г