Ответ:

дано

V(HCL) = 500 mL

p(HCL) = 1.1 g/mL

W(HCL) = 0.2

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m(Zn) - ?

V(H2) - ?

m(HCL) = V(HCL) * p(HCL) * W(HCL) = 500 * 1.1*0.2 = 110 g

Zn + 2HCL-->ZnCL2  + H2

M(HCL) = 36.5 g/mol

n(HCL) = m/M = 110 / 36.5  = 3 mol

n(Zn) = 2n(HCL)

n(Zn) =  3 / 2= 1.5 mol

M(Zn) = 65 g/mol

m(Zn) = n*M =  1.5* 65 = 97.5 g

2n(HCL) = n(H2)

n(H2) = 3 / 2= 1.5 mol

V(H2) = n*Vm = 1.5 * 22.4 = 33.6 L

ответ 33.6 л ,  97.5 гр

Объяснение: