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Lincik
@Lincik
October 2021
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Рассчитайте количество вещества метаналя, содержащегося в растворе объемом 1,5 л (плотность раствора равна 1,06 г/мл). Массовая доля вещества равна 20%
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wasurenagusa
Verified answer
CH2O
V р-ра = 1,5 л = 1500 мл
m р-ра = pV = 1500*1,06 = 1590 г
ω% =
m в-ва*100%/
m р-ра
m в-ва = 1590*0,2 = 318 г
n(CH2O) = 318/30 = 10,6 моль
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Answers & Comments
Verified answer
CH2OV р-ра = 1,5 л = 1500 мл
m р-ра = pV = 1500*1,06 = 1590 г
ω% = m в-ва*100%/m р-ра
m в-ва = 1590*0,2 = 318 г
n(CH2O) = 318/30 = 10,6 моль