NaOH+H2S=NaHS+H2Om(р-ра натрий оаш)=40x1.044=41.76гm(самого NaOH)=41.76x0.06=2.5056гn(NaOH)=n(H2S)=2.5056/40=0.06264мольV(H2S)=0.06264x22.4=примерно 1.403литра
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NaOH+H2S=NaHS+H2O
m(р-ра натрий оаш)=40x1.044=41.76г
m(самого NaOH)=41.76x0.06=2.5056г
n(NaOH)=n(H2S)=2.5056/40=0.06264моль
V(H2S)=0.06264x22.4=примерно 1.403литра