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alyonasmirnova2
@alyonasmirnova2
June 2022
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Какой объем кислорода потребуется для полного сгорания 31,25 мл этанола если p=0,8 г/мл
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tdd2014
C2H5OH + 3O2 → 2CO2 + 3H2O
m(C2H5OH)=V*p=31,25*0,8=25 г
n(C2H5OH)=m/M=25/46=0,543 моль
n(C2H5OH):n(O2)=1:3 → n(O2)=0,543*3=1,63 моль
V(O2)=n*Vm=1,63*22,4=36,52 л
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Answers & Comments
m(C2H5OH)=V*p=31,25*0,8=25 г
n(C2H5OH)=m/M=25/46=0,543 моль
n(C2H5OH):n(O2)=1:3 → n(O2)=0,543*3=1,63 моль
V(O2)=n*Vm=1,63*22,4=36,52 л