Ответ:
дано
V(C2H5OH) = 2 L = 2000 mL
W(C2H5OH) = 80%
p(C2H5OH) = 0.8 g/mL
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V(C2H4) - ?
m(C2H5OH) = V(C2H5OH)*W(C2H5OH)*p(C2H5OH) / 100%
m(C2H5OH) = 2000 * 80%*0.8 / 100% = 1280 g
C2H5OH-->C2H4+H2O
M(C2H5OH) = 46 g/mol
n(C2H5OH)= m(C2H5OH) / M(C2H5OH) = 1280 / 46 = 27.83 mol
n(C2H5OH) = n(C2H4)
V(C2H4) = n*Vm = 27.83 * 22.4 = 623,4 L
ответ 623.4 л
Объяснение:
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Ответ:
дано
V(C2H5OH) = 2 L = 2000 mL
W(C2H5OH) = 80%
p(C2H5OH) = 0.8 g/mL
------------------------------
V(C2H4) - ?
m(C2H5OH) = V(C2H5OH)*W(C2H5OH)*p(C2H5OH) / 100%
m(C2H5OH) = 2000 * 80%*0.8 / 100% = 1280 g
C2H5OH-->C2H4+H2O
M(C2H5OH) = 46 g/mol
n(C2H5OH)= m(C2H5OH) / M(C2H5OH) = 1280 / 46 = 27.83 mol
n(C2H5OH) = n(C2H4)
V(C2H4) = n*Vm = 27.83 * 22.4 = 623,4 L
ответ 623.4 л
Объяснение: