Какая масса фосфорной кислоты содержится в 830 мл 20% раствора с плотностью 1,05 г/мл. Created by nikkom553. himiya-ru

мл...

100ethereals

Verified answer

M(p-p)=p*V=1,05г/мл*830мл=871,5 г
m(H3PO4)=m(p-p)*w(H3PO4)=871,5г*0,2=174,3 г

0 votes Thanks 0

mrvladimir2

Verified answer

M(p-pa H3PO4) = V(p-pa H3PO4)*p(p-pa H3PO4)
m(p-pa H3PO4)= 830 мл*1,05 г/мл = 871,5 г
m(H3PO4)=m(p-pa H3PO4)*ω(H3PO4)/100%
m(H3PO4)= 871,5 г*20%/100% = 174,3 г
Ответ: 174,3 г

0 votes Thanks 1

Answers & Comments

Verified answer

Verified answer

v treugolnike avs ugol s pryamoj ugol a raven 30 gradusov vs 25 sm najdite1c584d4eb194cd896d3d176a44401432 43671

otvette pozhalujsta hotya by na nekotorye zadaniya complete the sentences with

najdite naibolshee shestiznachnoe chislo dayushee pri delenii na 5 7 11 13 ostato2949acf522e52b384940d1af3e8bfa77 5268

reshite pozhalujsta ochen nuzhno workbook 6

pri kakom znachenii a uravnenie 3x 6y10 i x ay5 ne imeyut obshego resheniya38e8a8a4f68941f4e4f8c60d5e34275b 34824

v treugolnike avs ugol s pryamoj ugol a raven 30 gradusov vs 25 sm najdite

pri kakom znachenii a uravnenie 3x 6y10 i x ay5 ne imeyut obshego resheniya

ploshad bolshogo porshnya gidravlicheskoj mashiny 2 m2 ploshad malogo 004 m2 kako

obrazujte predlozheniya v passive voice 1my father reads newspapers every morni

otgadajte slova 1 ranshe primenitelno k etomu ustrojstvu govorili evm 2ochen

рекомендуемые вопросы

Helpful Links

Helpful Social