мне надо решить задание
1)2х2-72=0
2)2х2+12х+10=0
3)х2-9х+18=0
4)х4-11х2+18=0
1)2х2-72=0
2)2х2+12х+10=0
3)х2-9х+18=0
4)х4-11х2+18=0
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Answers & Comments
1) 2х2-72=0
2(х2-36)=0
(х-6)(х+6)=0
х=6 х=-6
2) 2х2+12х+10=0
Д=12^2-4×2×10=144-80=64
х1=-12+8/4=-1
х2=-12-8/4=-5
3) х2-9х+18=0
Д=(-9)^2-4×1×18=81-72=9
х1=9+3/2=6
х2=9-3/2=3
4) х4-11х2+18=0
у=х^2
у2-11у+18=0
Д=11^2-4×1×18=121-72=49
у1=11+7/2=9
у2=11-7/2=2