m(MnO2) = 217.5 g
m(Al) - ?
n(MnO2) = 217.5 g / 87 g / mol = 2.5 mol2.5 mol x mol
3MnO2 + 4Al = 2Al2O3 + 3Mn
3 mol 4 mol
3:2.5 = 4:x
3x = 10
x = 3.333
m(Al) = 3.333 mol * 27 g / mol = 89.991 g = 90 g
Відповідь: 90 g .
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Answers & Comments
m(MnO2) = 217.5 g
m(Al) - ?
n(MnO2) = 217.5 g / 87 g / mol = 2.5 mol
2.5 mol x mol
3MnO2 + 4Al = 2Al2O3 + 3Mn
3 mol 4 mol
3:2.5 = 4:x
3x = 10
x = 3.333
m(Al) = 3.333 mol * 27 g / mol = 89.991 g = 90 g
Відповідь: 90 g .