МНОГО БАЛЛОВ!!!!!!!!!!!!. Created by ds1842. algebra-ru

МНОГО БАЛЛОВ!!!!!!!!!!!!...

polinasmart 1
tg(4πx/3-π/6)=√3
4πx/3-π/6=π/3+πn
8πx-π=2π+6πn
8x-1=2+6n
8x=3+6n
x=3/8+3n/4,n∈z
наибольший отрицательный х=-3/8 при n=-1
2
sin(10πx/16)=-√2/2
10πx/16=-π/4+2πn U 10πx/16=5π/4+2πn
10πx=-4π+32πn U 10πx=20π+32πn
x=-0,4+3,2n,n∈z U x=2+3,2n,n∈z
наименьший положительный х=2 при n=0

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sedinalana

Verified answer

1. tg(4πx/3 - π/6) = √3
4πx/3 - π/6 = π/3 + πn, n∈Z
x = 3/8 + 3n/4, n∈Z
n=-1: x =3/8 - 3/4 = -3/8

2. sin(10πx/16) = -√2/2
10πx/16 = (-1)^n 5π/4 + πn, n∈Z
x = (-1)^n * 2 + 1.6n, n∈Z
n = 0: x = 2

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